March 19, 2020 at 2:22 pm

peteroznewman

Subscriber

Say you had a beam that was symmetric, 100 mm long and a cross section of 20 x 6 mm and you wanted to apply a tension load along the length. Let's say the tension load was 64 N, so in the full model you have 64 N at each end (which won't solve, by the way).

If the first symmetry plane was to cut it in half at the center so it was only 50 mm long, you still have 64 N at the end you kept.

If the second symmetry plane was to cut it in half in the 20 mm direction, now there is only half the cross section, so that would have an end load of 32 N.

If the third symmetry plane was to cut it in half in the 6 mm direction, now there is only a quarter of the cross section, so that would have an end load of 16 N.