jehanxt
Subscriber
There have been few typo in the question. Below is the light beam characteristics and Im looking what is the FWHM angle or is the above figure in the problem is correct? IS there a way to find this FWHM angle?nSpectrum Distribution = GaussiannMean Wavelength 425nmnHalf Width of Gaussian=5nmnEmitted Power=100WnAir area(r=1mm) =3.14mm2nlight beam in perpendicular to the surfacen
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