July 20, 2020 at 1:36 pmThePhontyfexSubscriber
I wanted to ask if it is possible to make a mesh with cubic elements at 27 nodes. If I select "ELEMENT order = quadratic" the element has only 20 nodes. Thanks in advance for your reply!
July 22, 2020 at 12:18 pmAniketAnsys Employee
by default we do not have any element in Mechanical that will have 27 cubes, I am also doubtful if one can write their own element with 27 nodes that solver will understand.
Can you explain your query in bit more details?
July 23, 2020 at 8:03 amThePhontyfexSubscriber
I have to analyze simple geometries. for example a beam. the mesh divides the beam into elements that have the shape of a cube. The nodes that have these cubes depend on "element order". if I select "Linear" the cubes will have nodes only at the vertices, if I select "quadratic" in addition to the vertices, the cubes have nodes in the center of the segment (therefore they have 20 nodes). I need these elements to have nodes also in the center of the faces and in the center of the cube itself. to better explain myself I am attaching a drawing.
July 23, 2020 at 3:32 pmAniketAnsys Employee
wouldn't the third case be the same or similar to using the linear element with half the size?
July 23, 2020 at 5:26 pmThePhontyfexSubscriberYes, you're right! This can be a solution! Thank you!
But, Sorry if I insist, Is not possible to do with the third case? because as you suggested the number of elements would become much larger
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