October 6, 2022 at 2:07 pmjavat33489Subscriber
I did two tests and calculations.
a) Stretching the sample to break steel in the form of a dumbbell. According to the test, the force was 100,000N. According to the calculation 950000N. The calculation error is 500 kg. At the same time, I used bilinear kinematic hardening, which I calculated from the yield strength and strength.
b) Stretching a part from a pipe. According to the test, the force was 9,000,000N. According to the calculation of 200000N. The calculation error is very large.
Why is this happening? According to the first calculation, the material was selected. The place of the break shows correctly, but according to the calculation, too little effort.
October 9, 2022 at 11:07 ampeteroznewmanSubscriber
What do you mean by “stretching a part from a pipe”?
In this assembly, which part is being held fixed? Where on that part is it being held?
In this assembly, which part is being pulled? Where on that part is it being pulled?
How much stretching is being done? Where on the assembly does the break occur?
Please show the entire Force-Displacement plot from the pipe assembly test.
In the simulation, what is the significance of 200 kN? Why do you say that force in the simulation matches a force of 9,000 kN in the test?
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