July 24, 2023 at 11:27 pmJonathan ParkSubscriber
I have a 2D CFD model where rectangle 1 is inserted within rectangle 2. Rectangle 1 represents the cross section of a material with finite length and width, and rectangle 2 represents the cross section of a vacuum chamber where the material is placed. I have to model the heat flux boundary condition onto the surface of rectangle 1 as a heat source boundary condition. Could there be a way to convert heat flux to heat source using UDF code? Heat flux is non-uniform, and I can't really convert heat flux to heat source boundary condition by hand because this is a 2D problem.
July 25, 2023 at 9:30 am
July 25, 2023 at 6:32 pmJonathan ParkSubscriber
I only have a given non-uniform heat flux distribution as a function of x and y, which is set onto the material. Howeer, in my problem, since the external surface of the material is the internal surface of the vacuum chamber, I must treat treat the incoming heat flux as heat source occuring within the material.
I understand that if I had a heat source given in my problem, I would directly use Heat Generation. However, I’m only given a heat flux which must be converted to heat source.
For Shell Conduction, if I’m not given a heat source but just a heat flux. In ‘Heat Generation Rate’, can I just divide heat flux by the thickness even if the heat flux q”(x,y) is non-uniform, 2D, dependent on x and y? Does shell conduction consider takes account of both directions normal to the wall and along the wall (or both x and y directions) ? I thought shell conduction only considers heat flux normal to the surface.
July 26, 2023 at 7:53 amRobAnsys Employee
You need to figure out what's in the model. If the block is present in both cases, you can use a source into the solid volume. Or you add a flux through a surface, a profile may be suitable for that.
Shell conduction means heat can conduct along a thin wall, otherwise it can't. The heat generation doesn't need shell conduction and is a way to get heat into a thin wall: typical use case could be underfloor heating or heating jackets on pipes.
July 26, 2023 at 6:03 pmJonathan ParkSubscriber
Yes, the block is present in both cases. Both the reactor (larger rectangle) and substrate (smaller rectangle) are cylindrical cross sections. The substrate has a thickness of 5 mm, so it's thin. Is there a way to apply source into the solid volume (W/m^3) if I only have the non-uniform heat flux profile (W/m^2)? The reason I can't apply the heat flux is because the external surface of the substrate is the internal surface of the CFD model of the reactor. Therefore I must convert my heat flux distribution into a volumetric heat source.
July 27, 2023 at 9:07 amRobAnsys Employee
If you know the respective volume & area then yes, you can get the correct number of Watts into the system. What you can't do is add a volume source bounded by a heat flux boundary: the source volume will either be 1K or 5000K as Fluent hits the solver (default) limiters.
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