Tagged: Discovery AIM, structures
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July 28, 2020 at 9:46 am
ma.e.ebol
SubscriberHi,
Good day.
I would like to ask the difference between this simulation. In the drawing attach, we already fabricated this rack and we found out the channel on the highlighted portion already bend. But in Discovery aim, During simulation of physics and result, no indication of bending or stress can be found. We expect also at ANSYS that stress can be define considering the no load above the rack since in actual it already does.
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July 29, 2020 at 11:20 am
Charudatta Bandgar
SubscriberHello THPAL Engineering ,
The results from AIM will depend on how the boundary conditions are applied and how close they represent the real-life testing scenario. The more accurate the representation of the actual scenario, the more accurate these results can be correlated. I would request you to cross-check the BCs.
Can you please explain to me the experimental setup and how the loads applied are calculated? Understanding the problem statement, the experimental BCs, and FEA representation can give us a clue to understanding the difference you are experiencing.
Regards.
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August 1, 2020 at 8:53 am
ma.e.ebol
SubscriberHello Charudatta,
The point of our inquiry on the above email is does the Discovery Aim can detect the self load or self weight of the material without putting any load. It means in actual scenario the platform is made of steel therefore steel has weight that may contribute to the bending of the structure without prior load.
The platform or rack is already done but still without load yet it is already bending. Therefore we would like to know if the ANSYS has that features to detect self weight of the material?
Your deeper knowledge and assistance will help us to move forward on this concern
Thank you very much
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August 3, 2020 at 5:09 am
Charudatta Bandgar
SubscriberHello THPAL Engineering ,
Thanks for clarifying your doubt.
does the Discovery Aim can detect the self load or self weight of the material without putting any load.
To apply self-load of the structure you can use inertia load. Inertia itself is not a load, but it causes loads (forces) to be developed in the bodies opposite in direction to the specified accelerations, which in this case can be used to define gravity. You can refer to the image attached to understand the way you can add gravity to the system.
Regards.
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