 ## General Mechanical

Topics relate to Mechanical Enterprise, Motion, Additive Print and more

• User196534
Subscriber

Hello to all,

I am trying to define an ellipsoidal section of a beam (BEAM 188) via the ASEC function.

Ansys documentation shows the following data to be entered in SECDATA:

A, Iyy, Iyz, Izz, Iw, J, CGy, CGz, SHy, SHz, TKz, TKy
where
A = Area of the section
Iyy = Moment of inertia about the y axis
Iyz = Product of inertia
Izz = Moment of inertia about the z axis
Iw = Deformation constant
J = Torsion constant
CGy = y coordinate of the centroid
CGz = z coordinate of the centroid
SHy = y coordinate of the shear center
SHz = z coordinate of the shear center
TKz = Thickness along the Z axis (maximum height)
TKy = Thickness along the Y axis (maximum width)

My ellipse has a dimension of 60 cm along the y axis and 30 cm along the x axis. Starting from the centroid, I have TKy = 30 cm and TKz = 15 cm.

Here is the data I get by entering (A, Iyy, Izz, J, TKz, TKy):
Area = 1360.5
Iyy = 77939.
Iyz = 0.0000
Izz = 0.29275E+06
Warping Constant = 0.0000
Torsion Constant = 0.58550E+06
Centroid Y = 0.0000
Centroid Z = 0.0000
Shear Center Y = 0.0000
Shear Center Z = 0.0000
Shear Correction-xy = 1.0000
Shear Correction-yz = 0.0000
Shear Correction-xz = 1.0000
Maximum height = 15
Maximum width = 30

My question is the following.
No matter what value I enter for TKz and TKy, the displacement of my beam is always the same. I tried with zero values (TKz = 0 cm, TKy = 0 cm) and extreme values (TKz = 100,000 cm, TKy = 100,000 cm).

Do you know what is the impact of TKz and TKy and if they correspond to the values I entered?

Here is a piece of my Apdl code if it helps:

SECTYPE,1, BEAM, ASEC,di, 0
SECOFFSET, CENT
SECDATA, A_di, Iy_di, , Iz_di, , J_di, , , ,TKz ,TKy, ,

Thanks to those who will take the time to answer, I hope I have been clear enough in my explanations.

Do not hesitate to ask me questions if this is not clear enough.

Have a good day !

• Ashish Khemka
Ansys Employee

Hi,

Regards,

Ashish Khemka

• User196534
Subscriber

Hi,

I am applying a force load. 