October 14, 2022 at 8:33 amKazuma YamashitaSubscriber
I have a simple question about the definition of TE/TM polarizations in FDTD.
I think that in general optics, the TE (Transverse Electric) polarization - the electric field is perpendicular to the plane of incidence - corresponds to s-polarization and the TM (Transverse Magnetic) polarization - the magnetic field is perpendicular to the plane of incidence - corresponds to p-polarization.
However, I found that this relation is opposite in FDTD simulations: when I use a movie monitor in 2D simulations with p-polarization, the output file becomes "file name_monitor name_TE."
Could anyone please tell me why this is?
October 14, 2022 at 6:18 pmGuilin SunAnsys Employee
In general, TE/TM is not uniquely defined. Actually they can be opposit as you observed.
BTW: I wrote a post in Chinese regarding to this. If you can use google translate please have a look: https://forum.ansys.com/forums/topic/ansys-insight-youguantetmpianzhenyijimoshiguangyuandewenti/#post-176494
October 17, 2022 at 5:03 amKazuma YamashitaSubscriber
Thank you for your reply.
Now I understand that the reason why 2D FDTD simulations give unexpected definition of polarization comes from the definition of field components in 2D FDTD:
TE: Ex, Ey, Hz
TM: Hx, Hy, Ez
But I am wondering why the TE mode can be called TE (transverse electric) in this definition. What is the TE wave (Ex, Ey) transverse to?
October 17, 2022 at 4:19 pmGuilin SunAnsys Employee
October 18, 2022 at 1:19 amKazuma YamashitaSubscriber
Thank you very much for your help. I understand that it is simply a matter of definition in 2D-FDTD.
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