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January 2, 2023 at 1:12 pm
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January 3, 2023 at 6:11 pm
Guilin Sun
Ansys Employee频域归化主要是对频谱归化,并不是直接对光源输入振幅归化,参见
https://forum.ansys.com/forums/topic/ansys-insight-guanyuguangyuandeguihuawentipinpuhegonglu/
假设入射的电场振幅为1伏特每米,真空中磁场仅为其377分之一,即1/120pi 大约0.00265。因此,你得到的最大值0.00459已经接近翻倍了。
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January 4, 2023 at 5:43 am
1406967172
Subscriber假如我要得到的电磁场分别于光源的电磁场比较,那么我电场强度只需要除以1,磁场强度除以0.00265,请问这样做对吗
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January 4, 2023 at 5:35 pm
Guilin Sun
Ansys Employee对的,归化是指电场归一化(光源电场强度为1v/m),但是磁场并没有归一化,需要根据电磁场的关系计算入射磁场(如果不是平面波的话)。
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January 5, 2023 at 10:16 am
1406967172
Subscriber您说的如果不是平面波的话就要根据电磁场的关系计算入射磁场,我这个是平面波就直接能除以0.00265?
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January 5, 2023 at 4:58 pm
Guilin Sun
Ansys Employee平面波磁场与电场有简单的关系,是电场除以阻抗。当然可以用120Pi做分母计算H,或者从光源里提取磁场都可以(仿真后)。
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