December 12, 2017 at 10:34 amemirdegirmenliSubscriber
I'm working on finding modes of the cavity, especially Helmholtz mode by using acoustics ACT. I designed a basic model and I got some results but they do not match results which I got using Helmholtz resonator formula (below). I found some document about Helmholtz resonator in Acoustics ACT docs but it is not detailed
To find Helmholtz resonance, I defined surface of the hole as a 101325 Pa for 1 ATM air pressure condition. but I am not sure if this approach is correct. Because, pressure travel through the neck and in the air. We know neck length but don't know the distance traveled in the air. (l attached SpaceClaim folder (18.0) of my model)
maybe this model can be worked ??
December 14, 2017 at 9:38 pm
December 17, 2017 at 2:42 ampeteroznewmanSubscriber
I am gradually learning the ACT Acoustics Extension and worked most of the workshops that came with the documentation.
I am reading “The Science of Sound” 2nd Edition by Thomas D. Rossing. Example 4.3 is to find the first three modes of vibration of a pipe 750 mm long with one open end and one closed end (neglect end correction). The answer in the book is f1 = v/4L = 343/4(0.75) = 114 Hz, f2 = 3(343)/4(0.75) = 343 Hz and f3 = 5(343)/4(0.75) = 572 Hz. These frequencies are calculated from knowing the standing wave patterns of the first three modes. I built a Modal Acoustics model in ANSYS 18.2 and got excellent agreement.
Rossing provides a formula to calculate the frequency of a Helmholtz resonator in Section 2.3 and gives an example of a flask with a 980 mm diameter sphere, a 30 mm diameter neck that is 100 mm long.
Rossing formula f = 207 Hz
Acoustic model f = 232 Hz.
CYLINDER by Emir
Your formula f = 262 Hz
Acoustic model f = 299 Hz
Rossing formula f = 346 Hz
Rossing says that open pipes have an “end effect” that adds to the length of typically 0.61D, while the formula you gave seems to have an “end effect” correction of 0.75D. I find it interesting that if I zero out the end correction in your formula, I get the same value as the Rossing formula.
If I use a correction of 0.35D, then I get f = 298 Hz, which is very close to the acoustic model.
I hope some of this is useful for you.
December 20, 2017 at 7:56 amemirdegirmenliSubscriber
Thak you Peter, You researched very detailedly. Maybe we can define new hole length of the acoustic model by regarding "end effect" because we defined the end of the neck as a constant pressure (0 Mpa). Or we use original neck length and we define other body has compressible air condition for the open end. ? will test them, thank you again. Best, Emir
- You must be logged in to reply to this topic.
Earth Rescue – An Ansys Online Series
The climate crisis is here. But so is the human ingenuity to fight it. Earth Rescue reveals what visionary companies are doing today to engineer radical new ideas in the fight against climate change. Click here to watch the first episode.
Subscribe to the Ansys Blog to get great new content about the power of simulation delivered right to your email on a weekly basis. With content from Ansys experts, partners and customers you will learn about product development advances, thought leadership and trends and tips to better use Ansys tools. Sign up here.
- Saving & sharing of Working project files in .wbpz format
- An Unknown error occurred during solution. Check the Solver Output…..
- Understanding Force Convergence Solution Output
- Solver Pivot Warning in Beam Element Model
- Colors and Mesh Display
- How to calculate the residual stress on a coating by Vickers indentation?
- whether have the difference between using contact and target bodies
- What is the difference between bonded contact region and fixed joint
- The solver engine was unable to converge on a solution for the nonlinear problem as constrained.
- User manual
© 2023 Copyright ANSYS, Inc. All rights reserved.