焦点x−y平面中相应的Ex相位分布如何求？

- April 18, 2023 at 1:35 pm
  
  594
  Subscriber
  
  老师您好，在超透镜聚焦中会出现这样的相位图（如图b），请问在x-y平面中相应的Ex相位分布应该如何改这里的代码呢？
  E2_xy = farfieldexact3d('T',x,y,zm);
  E2_xy = pinch(sum(abs(E2_xy)^2,4));
  image(x*1e6,y*1e6,E2_xy,'x (um)','y (um)','|E|^2 (x-y plane)');
- April 18, 2023 at 5:11 pm
  
  Guilin Sun
  Ansys Employee
  
  farfieldexact3d 的结果是NxMxKx3xP，其中3 指的是Ex，Ey和Ez，所以你需要先提取Ex，比如用：
  Ex=pinch(E2_xy(:,:,:,1,:))
  这里的1是指Ex，2就是Ey。
  然后再计算位相：
  Ex_phase=angle(Ex)

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