November 7, 2018 at 5:20 pmjonsysSubscriber
On a simple sandwiched beam attached, I apply a displacement.
Like in the sketch below (representing the far edge of beam), the model will rotate and also the middle layer will get squeezed because of its low Youngs Modulus.
I am struggling to find a way to measure
- how much this middle layer is squeezed
- what is the value of d (or better 2d)
Any suggestions will be helpful.
attached is also the model.
November 8, 2018 at 12:05 amSandeep MedikondaAnsys Employee
See if you can create a remote point in the middle of the bottom or top beams. If you are not able to you can even use the approximate node in the middle. Then once the simulation has completed, Click on the Solution object in the Structure tree and then on Worksheet. Here select the position or the displacement U, scope it to the 2 points(Remote point, vertices or nodes) and evaluate the results. This should give you 2*d.
November 8, 2018 at 8:28 am
November 8, 2018 at 11:27 amRohith PatchigollaAnsys Employee
One more idea is use Relative Displacement ACT App, to create a co-ordinate system, which moves and rotates along with the top face (of the three faces), with Z axis normal to the face. Then you can scope any mid-side node of the middle face, extract nodal z displacement relative to this co-ordinate system, which will give you d.
You can find the APP at the below link in ANSYS APP store.
November 8, 2018 at 12:11 pmSandeep MedikondaAnsys Employee
Just use the nodes for position calculations in Solution>Worksheet>USUM for scoping? you can easily get 2*d here. That is just a warning and I believe it is caused by the way you are scoping the middle remote point. Look in the solver output for details. Here is a very good blog on remote objects which talks about visualizing and dealing with the messages they can generate.
P.S: Please take a moment to look at the Best Practices on the Student Community.
November 8, 2018 at 4:49 pmjonsysSubscriber
thank you Sandeep, but I did not understand your explanation. Probably in pictures it would be easier or just modifying the model and attaching.
November 8, 2018 at 6:42 pmSandeep MedikondaAnsys Employee
Let's say you have this beam.
you might just want to insert an user-defined result for the variable:
Upon Evaluation this will give you this result:
Note that I've inserted a user-defined co-ordinate axis at one of the nodes. If you are using the global coordinate system you might have to just subtract the min and max values in the contour plot.
November 16, 2018 at 9:26 amjonsysSubscriber
thank you very much; now everything is more clear now
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