 ## Electronics

Topics relate to HFSS, Maxwell, SIwave, Icepak, Electronics Enterprise and more

• Tatsuya Ueda
Subscriber

Prepare two squares of copper sheet with 1 mm on each side and place them 5 mm apart.
A high-frequency signal is passed through them. At this time, we want to measure the increase in resistance due to the skin effect. However, the resistance of the simulation result is higher than the resistance calculated by the equation.
How can I reduce the difference between the simulated and calculated resistance values? • Aymen
Ansys Employee

What are the resistance values you got? What is the equation you used?

• Tatsuya Ueda
Subscriber

Hello:

The figure shows the simulated resistance. This is considered to be the sum of the resistances of the two copper plates.
We want to know the resistance of one copper plate. As the two copper plates are the same size, we assume that half of the result obtained from the simulation is the resistance value from the simulation. The resistance R from the calculation is then calculated using the following formula.

R = 1/(σS)

S = 4δ( x - δ )

δ = 1/{(π*μ0*μr*σ*f)^(1/2)}

σ is the conductivity of copper at 20°C
S is the effective area
x is the length of one side of the copper sheet
δ is the skin depth
μ0 is the magnetic permeability in vacuum
μr is the non-permeability of the copper sheet
f is frequency
In the present figure, the simulated resistance at 100 GHz is about 27.2 Ω and the calculated resistance is about 20.6 Ω. We want to reduce the difference between these two values.
In case you are wondering, the above method worked well in Q3D Extractor. However, it is not working in 2D Extractor.  