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March 19, 2023 at 4:06 am
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Subscriber老师您好,有一个问题想要请教。
以市面上常见的波长 254 纳米、输入功率为30 瓦的紫外线灯为例,在正常工作距离(1米)上,其辐射强度为 90微瓦每平方厘米。这里的辐射强度应该如何计算呢?
如果我采用一束光线照射一个小球,那么如何求得这个小球所受的辐射量呢?
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March 20, 2023 at 9:53 pm
Guilin Sun
Ansys Employee你确认是要辐射强度而不是光学强度?前者请找到定义计算,后者参见
Ansys Insight: 光学强度、功率、电场强度平方的关系以及电磁能量
其它你需要先找到计算公式。FDTD给你电场,磁场,然后你再根据定义计算。
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3780
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2587
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1835
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1244
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600
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