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July 5, 2023 at 5:58 am
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July 5, 2023 at 7:11 am
zhu youyang
Subscriber -
July 5, 2023 at 7:12 am
zhu youyang
Subscriber我将code修改成下面就没问题了
#########################################################
# Perform the far field projection and image result
m="monitor"; # Monitor name
res = 500; # projection resolution
E2 = farfield3d(m,1,res,res,1,1,1,1.33);# this returns |E|^2 in the far field
ux = farfieldux(m,1,res,res);
uy = farfielduy(m,1,res,res);
image(ux,uy,E2,"","","|E|^2 at 1 m","polar");
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July 5, 2023 at 4:09 pm
Guilin Sun
Ansys Employee可能就是投射介质的折射率不同,不指定的话应该是用监视器中心点的折射率。折射率不同,偏转角就不同。
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July 5, 2023 at 4:16 pm
zhu youyang
Subscriber是的,我也这样认为,谢谢老师!
监视器中心点的折射率默认是1吗?
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July 5, 2023 at 4:45 pm
Guilin Sun
Ansys Employeehttps://optics.ansys.com/hc/en-us/articles/360034930693-farfield3d-Script-command
里面没有说,从监视器直接做远场时,监视器应该用所在中心位置的折射率数值。至少我测试的是这样。
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July 6, 2023 at 2:09 am
zhu youyang
Subscriber收到。
我的背景是水(n=1.33),所以我认为利用监视器直接做远场时,farfield3d中的index,我认为也设置为1.33,监视器应该用所在中心位置的折射率数值,这个是指样品材料内部还是出射表面,还是我前面理解的整个背景折射率呢?
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July 6, 2023 at 4:32 pm
Guilin Sun
Ansys Employee“指样品材料内部还是出射表面,还是我前面理解的整个背景折射率呢?”
监视器中心位置的折射率,与内部或者出射表面无关,是一个点,要做远场投射,监视器必须位于均匀介质中。那么监视器中心点的折射率就是所在位置的折射率,应该没有歧义。
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July 7, 2023 at 3:56 am
zhu youyang
Subscriber收到,谢谢。
如果我把监视器设在初设表面位置,这个时候它属于一个中间位置,应该怎么理解呢?
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July 7, 2023 at 3:54 pm
Guilin Sun
Ansys Employee你是说把监视器放在材料界面上吗?最好不要这样放,离开一个网格最好。如果一定要放,你可以加一个折射率监视器看看结果。这个时候就取决于网格了。
注意,监视器中心是指监视器本身尺寸的中心,即监视器Center位置。
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July 8, 2023 at 6:00 am
zhu youyang
Subscriber好的,谢谢解答
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