March 21, 2020 at 11:46 pmMarkusPSubscriber
Dear community members,
according to Fluent Theory Guide, the following second-order accurate discretization of the transient term is used in Fluent (for a fixed time step):
This formulation is obviously not applicable for the initial time step (n = 0), as there are no values available for the second previous time step (n - 1 = -1).
How does Fluent discretize the transient term in the initial time step?
March 23, 2020 at 7:58 pmKalyan GoparajuAnsys Employee
Unfortunately, I cannot disclose this on an open forum as it may be proprietary. In general however, such scenarios are usually handled by just assuming that at n-1=n. Another approach could be treating the first iteration via a first order accurate scheme and rest of the iterations via 2nd order schemes.
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