Fluids

Fluids

Topics relate to Fluent, CFX, Turbogrid and more

Single reference frame

    • cs437
      Subscriber

      For symmetric geometry, the SRF could be applied; however, the centrifugal force or non-intertial term needs to be introduces. Therefore, I would like to know how to apply centrifugal force in this case. Because for SRF, wall is moving although it is opposite to the actual system.


      Does ANSYS Fluent has a function that the centrifugal force can be added? 


       


      Best regards,


       

    • Rob
      Ansys Employee

      What applies the force in your model? Ie what are you modelling?

    • cs437
      Subscriber

      I try to model mixing stirred tanks. For SRF, the wall is moving, which is opposite to the actual system. That is why I need to take an account of centrifugal force or introduce non-inertial term into the modeling. Do you have any options on ANSYS Fluent on that? Please suggest.


       


      Best regards,

    • cs437
      Subscriber

      I try to model mixing stirred tanks. For SRF, the wall is moving, which is opposite to the actual system. That is why I need to take an account of centrifugal force or introduce non-inertial term into the modeling. Do you have any options on ANSYS Fluent on that? Please suggest


       

    • cs437
      Subscriber

      Hi, 


       


      I would like to know how to decide to do SRF or MRF when the problem is symmetry and no stationary parts (i.e., baffle, outlet) in the tank. I found a lot of paper preferred to do MRF instead even in symmetry case. Is the velocity solver different since SRF we stand in the impeller position so it will be relative velocity instead of absolute velocity in most cases? Another question is to do periodic boundary instead of full simulation. What are the disadvantages and advantages? I noticed that this should save more cells and simulation time and we can mirror the result at post-processing. What else besides those? If doing periodic, how do we define a boundary condition at the the top surface since it is no longer symmetry boundary condition?


       


      Thank you.


       


      Best regards,


       


      Chadakarn

Viewing 4 reply threads
  • You must be logged in to reply to this topic.