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June 3, 2020 at 1:27 am
Kobee
SubscriberHello, Anys community,
I need help to simulate a fast filling hydrogen tank problem. I have found some papers published
https://pdfs.semanticscholar.org/f20d/6e53fc1795ca4470731959f7558e7436c4d4.pdf
https://www.sciencedirect.com/science/article/pii/S0360319916307078
I have read these papers but I wanna know if anyone has a tutorial or any guide step by step to help me with an example.
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June 3, 2020 at 5:30 am
DrAmine
Ansys EmployeeNo there is no tutorial which I can share with you. Just describe what you want to do and we try to provide guidance. Do not expect that we will go through the papers you listed.
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June 4, 2020 at 4:47 am
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June 4, 2020 at 4:47 am
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June 4, 2020 at 5:39 am
DrAmine
Ansys EmployeeThe customization manual goes through writing UDF profile. If you have experimental data for the temperature at inlet you can use profile files. Check the user's guide as they need to follow certain forma ( I guess with CSV format it is straightforward).
1/Use pressure based solver. There is no need to use density based solver here. Use the coupled solver
2/Use SST turbulence model. Ensure a relative good resolved boundary layer at walls
3/Are you expecting a supersonic inlet? Pleas check the values for sound speed. Also the intial gauge pressure at inlet is only used whenver it is supersonic at inlet.
4/Probably the time step size is large. You should use rather conservative settings
5/The temperature at inlet is total temperature and not static temperature: that means if you some overshoots at start of the run it will probably affect the temperature level.
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June 5, 2020 at 3:07 pm
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June 9, 2020 at 5:45 pm
Kobee
SubscriberFor anyone facing a similar problem like mine, you can define the transient inlet boundary condition by checking out this video
Thanks
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June 9, 2020 at 7:31 pm
RK
Ansys EmployeeHello,
What is the Mach number at the inlet?
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June 11, 2020 at 3:59 pm
Kobee
SubscriberFrom the last trial I did, the velocity contour was reading 2.23x10^3m/s at the inlet. This mean the M#=2.23x10^3/343=6.5.
I don't know if this figure is ridiculous but am open for suggestions sir.
Thanks for the reply.
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