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September 25, 2018 at 4:15 pm
jackhero
Subscriber -
September 25, 2018 at 4:47 pm
Sandeep Medikonda
Ansys EmployeeJack, I moved your question to a new thread as the old was getting too long and difficult to follow.
Coming to your question, this is strange as I am able to define this without problems in 19.0
Maybe someone else with an academic license can confirm this for me? Also, if you are able to, try and upgrade to the newer version?
What kind of Fracture are you trying to model? Interface or Contact?
I quickly tested this on a simple 2 element model and works without any problems.
Regards,
Sandeep
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September 26, 2018 at 6:45 am
jackhero
SubscriberThank you for your reply.
Maybe I did not clearly explain the problem. Your first image is from the Engineering Data section, at Engineering Data I am able to define all of the CZM (whether be Fracture or Exponential or Bilinear or Separation). I am facing problem in the Ansys Mechanical. The geometry (axisymmetry) is shown in the image along with the boundary conditions.
The contact is bonded and the formulation is selected as Pure penalty. I intend to simualte the contact debonding using the CZM to verify the experimental results, explained in this post.
For the CZM issue I am having is as follows. In the Fracture > Contact Debonding > Material, if I select CZM Frac (fracture based CZM as defined in Engineering data) or CZM Sep (Separation based CZM as defined in Engineering data) no problem occurs as shown in the two images below.
But if I select either CZM Expo (Exponential based CZM as defined in Engineering Data) or CZM Bi (Bilinear based CZM as defined in Engineering Data), I get the question mark at Fracture tree and Solution Tree. And I can not proceed further from here if I choose either Expo or Bi CZM.
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September 26, 2018 at 4:47 pm
Sandeep Medikonda
Ansys EmployeeHi Jack,
Those options are available only for delamination, not debonding. Debonding uses contact elements so the pre-damage stiffness is governed by contact elements. Delamination uses interface elements, which can have their own stiffness.
Hope that clarifies?
Regards,
Sandeep
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