Velocity Outlet Analysis in Nozzle

- April 16, 2023 at 12:39 am
  
  Muhammad Bagas Kamal
  Subscriber
  
  Do you guys know, why the velocity output of the viscous model (based on my simulation) is more stable than the inviscid model. Isn't it that in the Inviscid model the viscosity is neglected and fluid friction is also ignored, while the viscouse model takes into account the effects of fluid viscosity and friction. As I know in inviscid model the flow is more stable, symmetrical and without boundary layer. For those of you who want to share their insights, I'd be happy for you. Thanks in advance
- April 19, 2023 at 3:35 am
  
  Mohamad Faruq Imaduddin
  Subscriber
  
  Yes, you are correct Bagas in your understanding of the differences between the inviscid and viscous models. In the inviscid model, the fluid viscosity and friction are ignored, which results in a flow that is more symmetrical and without boundary layers. However, this can also lead to instabilities in the flow.
  
  On the other hand, in the viscous model, the effects of fluid viscosity and friction are taken into account, resulting in a more stable flow. This is because the viscosity and friction help to dampen out instabilities in the flow.
  
  In general, the choice of model depends on the specific problem you are trying to solve. If the flow is expected to be relatively simple and symmetrical, the inviscid model may be sufficient. However, if the flow is more complex or if stability is a concern, the viscous model may be necessary.
  
  It’s also worth noting that the choice of numerical method used to solve the equations can also have an impact on the stability of the solution. Some numerical methods may be more prone to numerical instabilities than others, and the choice of method should be carefully considered based on the specific problem being solved.
  - April 20, 2023 at 4:47 pm
    
    Robert Anderson
    Subscriber
    
    "In general, the choice of model depends on the specific problem you are trying to solve. If the flow is expected to be relatively simple and symmetrical, the inviscid model may be sufficient. However, if the flow is more complex or if stability is a concern, the viscous model may be necessary.
    
    It’s also worth noting that the choice of numerical method used to solve the equations can also have an impact on the stability of the solution. Some numerical methods may be more prone to numerical instabilities than others, and the choice of method should be carefully considered based on the specific problem being solved."
    Yes, I totally agree with you.
    cubes 2048

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